CBSE Class 10 Biology Heredity Previous Year Questions
Help your child master CBSE Class 10 Biology Heredity with this curated collection of previous year board questions spanning 2016–2024. Every question comes with a detailed step-by-step solution covering Mendel’s laws, dominant and recessive traits, monohybrid and dihybrid crosses, sex determination, and more — the topics that consistently carry marks in the board exam.
CBSE Class 10 Biology Heredity — Questions with Solutions
Explanation: When a pure tall plant (TT) is crossed with a pure dwarf plant (tt), the F₁ generation consists entirely of tall plants (Tt).
When the F₁ plants undergo self-pollination, the F₂ generation produces 3 tall plants and 1 dwarf plant.
Hence:
• F₁ Generation: 100% Tall
• F₂ Generation: 75% Tall, 25% Dwarf
Explanation: The variations in appearance are most likely due to random genetic changes and the combination of genes during reproduction, which can result in different phenotypes.
Explanation: Genetic information, including the patterns on the wings, is passed on from parent moths to their offspring.
One of the following was observed in 20 years after this event and is believed to be linked to it. Which one could it be?
Explanation: With reduced pollution and cleaner environments, the advantage of the melanistic form (dark-coloured moths) decreased, leading to an increase in the number of peppered moths.
Explanation: The passage suggests that the presence of different moth types is influenced by chance, and survival benefits are determined by environmental factors.
Question: What are the chances of parents, both having attached earlobes, to have a child with attached earlobes?
Explanation: If both parents have attached earlobes, it means they carry two copies of the recessive allele (aa). Therefore, all their children will inherit one recessive allele from each parent, resulting in a 100% chance of having attached earlobes.
Reason (R): Cellular DNA is the information source for making proteins in the cell.
Mark the correct choice as:
(A) Both (A) and (R) are true and R is the correct explanation of (A).
(B) Both (A) and (R) are true but R is NOT the correct explanation of (A).
(C) (A) is true but (R) is false.
(D) (A) is false and (R) is true.
Explanation: Height in pea plants is controlled by the efficiency of enzymes. Plants with more growth hormones released grow taller. Thus, height is genetically controlled. Cellular DNA is the information source for making proteins, which in turn carry the information for the release of hormones. Hence R correctly explains A.
Reason (R): White colour gene is not passed on to the next generation.
Mark the correct choice as:
(A) Both (A) and (R) are true and R is the correct explanation of (A).
(B) Both (A) and (R) are true but R is NOT the correct explanation of (A).
(C) (A) is true but (R) is false.
(D) (A) is false and (R) is true.
Explanation: The gene for violet flowers is dominant over the gene for white flowers, so only violet flowers are expressed in the F₁ generation. The white colour gene IS passed on to the next generation but remains unexpressed as it is recessive. It reappears in the F₂ generation after selfing.
Reason (R): The black colour of the eyes is a dominant trait.
Mark the correct choice as:
(A) Both (A) and (R) are true and R is the correct explanation of (A).
(B) Both (A) and (R) are true but R is NOT the correct explanation of (A).
(C) (A) is true but (R) is false.
(D) (A) is false and (R) is true.
Explanation: A dominant trait is expressed even if only one allele for that trait is present. Since black (B) is dominant over brown (b), both BB and Bb will result in black eyes. Only bb will give brown eyes. Thus R correctly explains A.
Reason (R): If the egg cell carrying an X chromosome fuses with a sperm carrying a Y chromosome, the resulting child would be a boy.
Mark the correct choice as:
(A) Both (A) and (R) are true and R is the correct explanation of (A).
(B) Both (A) and (R) are true but R is NOT the correct explanation of (A).
(C) (A) is true but (R) is false.
(D) (A) is false and (R) is true.
Explanation: A zygote having two X chromosomes (XX) develops into a girl (female), not a boy. A zygote having one X and one Y chromosome (XY) develops into a boy (male). Hence Assertion is false. Reason is correct.
When a pure tall plant (TT) is crossed with a pure short plant (tt), all offspring in the F₁ generation are Tt (heterozygous tall). Since tallness (T) is the dominant trait, it is expressed in all F₁ plants, while dwarfness remains hidden.
It is a double-stranded molecule found in the nucleus of cells that contains the genetic instructions for the development, functioning, growth, and reproduction of all living organisms. Specific segments of DNA called genes code for the production of proteins that determine the traits of an organism.
Explanation:
• Suppose a plant possesses a gene for tallness. This gene gives instructions to the plant cell to produce more plant growth hormones, causing the plant to grow tall.
• On the other hand, if the plant has the gene for shortness, it will produce less plant growth hormones, resulting in a dwarf (short) plant.
Thus, genes directly control the traits of an organism through protein synthesis.

(a) Phenotypic Ratio: Red : White = 3 : 1
(b) Genotypic Ratio: Pure Red (RR) : Hybrid Red (Rr) : Pure White (rr) = 1 : 2 : 1

Result of Cross Between TT × Tt:
Phenotype: All plants are Tall.
Genotype Distribution:
• 50% Homozygous Tall (TT)
• 50% Heterozygous Tall (Tt)
Therefore, there will be zero (0) short pea plants in the progeny, as no tt genotype is produced.
• Field A produced brown-coloured seeds.
• Field B produced yellow-coloured seeds.
It was observed that in Field A, the offsprings showed only the parental trait for consecutive generations. In Field B, the majority of the offsprings showed variation in the progeny. What are the probable reasons for these differences?
• In Field B, variation is seen because of recombination of genes as cross-pollination is taking place. When pollen from one plant fertilises another, new gene combinations arise, leading to variation in the progeny.
In order to determine whether an accident victim is male or female, which cells can be used and why?
Reason: Barr bodies are the condensed, inactive X chromosomes visible in the cells of females (XX). Females have one Barr body per cell, while males (XY) typically have none. By examining buccal cells under a microscope, forensic experts can determine the sex of the victim based on the presence or absence of Barr bodies.
Given: A green-stemmed tomato plant (GG) is crossed with a purple-stemmed tomato plant (gg).
(i) What will the F₁ generation look like?
(ii) What are the genotypic and phenotypic ratios in F₂ generation?
(iii) What conclusion can be drawn about the dominance of traits?
All the plants in the F₁ progeny will have green-coloured stems with genotype Gg, since green (G) is dominant over purple (g).
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(ii) F₂ Generation (Gg × Gg):

• Genotypic Ratio: GG : Gg : gg = 1 : 2 : 1
• Phenotypic Ratio: Green : Purple = 3 : 1
(iii) Conclusion:
The green stem colour is dominant over the purple stem colour. Recessive traits are not expressed in the F₁ generation (heterozygous condition) but get expressed in the F₂ generation (homozygous condition). This is known as the Law of Dominance.
When F₁ plants are self-pollinated, which new combinations of characters are expected in F₂ progeny? How many seeds with these new combinations will be produced when a total of 160 seeds are formed in F₂ generation? Explain with reason.
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The new combinations of characters expected in the F₂ generation are:
• Round Green = (3/16) × 160 = 30 seeds
• Wrinkled Yellow = (3/16) × 160 = 30 seeds
Explanation: The new combinations are produced because of the independent inheritance of seed shape and seed colour traits, as explained by Mendel’s Law of Independent Assortment.
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Analyse the result and describe the mechanism of inheritance which explains the results.
Analysis:
This indicates that the progeny plants have not inherited the whole set of genes from each parent. Every germ cell takes one chromosome from the pair of maternal and paternal chromosomes.
Mechanism:
When two germ cells combine, the segregation of one pair of characters is independent of the other pair of characters. This is explained by Mendel’s Law of Independent Assortment, which states that alleles of different genes are distributed to gametes independently of one another.
• Women have a perfect pair of sex chromosomes (XX) — they can only produce egg cells carrying the X chromosome.
• Men have a mismatched pair of sex chromosomes (XY) — they produce two types of sperm: those carrying X and those carrying Y, in equal numbers.
All children inherit an X chromosome from their mother. The sex of the child is determined by what they inherit from their father:
• Child inheriting X from father → Girl (XX)
• Child inheriting Y from father → Boy (XY)
Since half the sperm carry X and half carry Y, there is always a 50% probability for either a boy or a girl.
• In some animals (e.g., turtles and crocodiles), the temperature at which fertilised eggs are kept determines whether the developing animal is male or female.
• In some animals like snail, an individual can change sex depending on environmental conditions.
2. Genetically Determined Sex:
In humans, a child who inherits an X-chromosome from the father will be a girl (XX), and one who inherits a Y-chromosome from the father will be a boy (XY). The sex is determined by the genetic makeup at the time of fertilisation.
(a) Gametes having both the round and yellow seed traits
(b) Offspring having the same genotype as the parents
(c) Offspring having the same phenotype as the parents
Since R is homozygous (RR), all gametes will carry R. The G locus is heterozygous (Gg), producing G and g gametes in equal ratio.
(a) Gametes having both round and yellow seed traits (RY):
Since yellow (Y) is not present in the parents (only G and g), the proportion of gametes with round and yellow traits = 50% (those carrying RG, as round is dominant; but note the answer given is 50%)
(b) Offspring having the same genotype as the parents (RRGg):
From Gg × Gg, genotype Gg = 50%. Since RR × RR = all RR, offspring with RRGg = 50%
(c) Offspring having the same phenotype as the parents (Round Green):
From Gg × Gg, genotypes GG + Gg = 75% show green. All offspring are RR (round). So round green = 75%
(b) Why are the traits acquired during the lifetime of an individual not inherited? Explain.
In a cross between a pair of contrasting characters, only one parental character will be expressed in the F₁ generation, which is called the dominant trait. The other, which does not express itself, is called the recessive trait.
Example: In pea plants, when a tall pea plant (TT) is crossed with a short pea plant (tt), all the progeny produced in the F₁ generation are tall (Tt). This proves that the gene for tallness is dominant over the gene for dwarfness, which cannot express itself in the presence of the dominant trait.
(b) Why acquired traits are not inherited:
Traits acquired by an organism during its lifetime are known as acquired traits. These traits are not inherited because they occur in somatic (body) cells only and do not cause any change in the DNA of the germ cells (sperm and egg). Since hereditary information is passed on through germ cells, only those changes that occur in the DNA of germ cells can be transmitted to the next generation.
(b) “Is it possible that a trait is inherited but may not be expressed in the next generation?” Give a suitable example to justify this statement.
Dominant Trait: The trait which expresses itself in the F₁ (first) generation after crossing contrasting (opposite) traits is known as the dominant character (trait).
Recessive Trait: The trait which is not expressed in the F₁ (first) generation after crossing contrasting (opposite) traits is known as the recessive character (trait).
(b) Inherited but not expressed:
Yes, it is possible that a trait is inherited but not expressed in the next generation.
Example: When a tall pea plant (TT) is crossed with a dwarf pea plant (tt), all F₁ plants are Tt (tall). The recessive trait of dwarfness is inherited (the ‘t’ allele is present) but is not expressed because the dominant ‘T’ allele masks it. The dwarfness trait reappears only in the F₂ generation when two Tt plants self-pollinate and some offspring receive tt genotype.

(a) Traits may be dominant or recessive?
(b) Inheritance of two traits is independent of each other?
Mendel crossed pure tall pea plants with pure dwarf pea plants. He observed only tall pea plants in the F₁ generation. On self-crossing of F₁ progeny, both tall and dwarf pea plants appeared in the F₂ generation in the ratio 3 : 1.
The appearance of tall character in F₁ shows tallness to be dominant. The absence of the dwarf character in F₁ and its reappearance in F₂ confirms that dwarfness is recessive.
(b) Inheritance of two traits is independent — Dihybrid Cross:
Mendel conducted a dihybrid cross (round yellow × wrinkled green seeds) and observed that though he started with two types of parents, he obtained four types of individuals in the F₂ generation in the ratio 9 : 3 : 3 : 1.
The appearance of new recombinations (round green and wrinkled yellow) in the F₂ generation along with parental type characters showed that traits are inherited independently of each other — this is Mendel’s Law of Independent Assortment.
(a) What do the F₁ progeny of tall plants with round seeds and short plants with wrinkled seeds look like? (1)
(b) Name the recessive traits in the above case. (1)
(c) Mention the type of the new combinations of plants obtained in F₂ progeny along with their ratio, if F₁ progeny was allowed to self-pollinate. (2)
OR If 1600 plants were obtained in F₂ progeny, write the number of plants having traits: (i) Tall with round seeds. (ii) Short with wrinkled seeds. Write the conclusion of the above experiment.
F₁ progeny will be heterozygous tall plants with round seeds (TtRr), as tallness and round seeds are the dominant traits.
(b) Recessive Traits:
The recessive traits are short plants and wrinkled seeds.
(c) New Combinations in F₂:

• Tall Round : Short Round : Tall Wrinkled : Short Wrinkled
• Phenotypic Ratio = 9 : 3 : 3 : 1
OR — If 1600 plants in F₂:
(i) Tall plants with round seeds = (9/16) × 1600 = 900
(ii) Short plants with wrinkled seeds = (1/16) × 1600 = 100
Conclusion: This experiment states the Law of Independent Assortment — the alleles of two or more different genes get sorted into gametes independently of one another.
(a) In what way are the sex chromosomes ‘X’ and ‘Y’ different in size? Name the mismatched pair of sex chromosomes in humans.
(b) Write the number of pair/pairs of sex chromosomes present in human beings. In which one of the parent (male/female) perfect pair/pairs of sex chromosome are present?
(c) Citing two examples, justify the statement “Sex of an individual is not always determined genetically.”
The Y chromosome is about one-third the size of the X chromosome. The X chromosome has about 900 genes, while the Y chromosome contains about 55 genes. The mismatched pair of sex chromosomes in humans is the XY pair, found in normal human males.
(b) Number of sex chromosome pairs in humans:
There is 1 pair of sex chromosomes present in human beings. Females have a perfect pair of sex chromosomes, i.e., XX.
(c) Sex not always genetically determined — two examples:
1. In some animals (e.g., turtles), the temperature at which fertilised eggs are kept determines whether the developing animal will be male or female.
2. In some animals like snails, an individual can change sex during its lifetime depending on environmental or social conditions.

